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Date: Sun, 12 May 2013 19:35:39 -0400
From: Ned Batchelder <ned@nedbatchelder.com>
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To: "Mr. Joe" <titanix88@gmail.com>
Subject: Re: Differences of "!=" operator behavior in python3 and python2 [ bug? ]
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Xref: csiph.com comp.lang.python:45211

On 5/12/2013 7:23 PM, Mr. Joe wrote:
> I seem to stumble upon a situation where "!=" operator misbehaves in
> python2.x. Not sure if it's my misunderstanding or a bug in python
> implementation. Here's a demo code to reproduce the behavior -
> """
> # -*- coding: utf-8 -*-
> from __future__ import unicode_literals, print_function
>
> class DemoClass(object):
>      def __init__(self, val):
>          self.val = val
>
>      def __eq__(self, other):
>          return self.val == other.val
>
> x = DemoClass('a')
> y = DemoClass('a')
>
> print("x == y: {0}".format(x == y))
> print("x != y: {0}".format(x != y))
> print("not x == y: {0}".format(not x == y))
> """
>
> In python3, the output is as expected:
> """
> x == y: True
> x != y: False
> not x == y: False
> """

In Python 3, if __ne__ isn't defined, "!=" will call __eq__ and negate 
the result.
> In python2.7.3, the output is:
> """
> x == y: True
> x != y: True
> not x == y: False
> """
> Which is not correct!!

In Python 2, "!=" only calls __ne__.  Since you don't have one defined, 
it's using the built-in object comparison, and since x and y are 
different objects, they are not equal to each other, so x != y is True.

> Thanks in advance for clarifications.
> Regards,
> TB