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From: Ian Kelly <ian.g.kelly@gmail.com>
Date: Thu, 28 Jul 2011 14:44:15 -0600
Subject: Re: list comprehension to do os.path.split_all ?
To: gry <georgeryoung@gmail.com>
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On Thu, Jul 28, 2011 at 2:18 PM, gry <georgeryoung@gmail.com> wrote:
> [python 2.7] I have a (linux) pathname that I'd like to split
> completely into a list of components, e.g.:
> =A0 '/home/gyoung/hacks/pathhack/foo.py' =A0--> =A0['home', 'gyoung',
> 'hacks', 'pathhack', 'foo.py']
>
> os.path.split gives me a tuple of dirname,basename, but there's no
> os.path.split_all function.
>
> I expect I can do this with some simple loop, but I have such faith in
> the wonderfulness of list comprehensions, that it seems like there
> should be a way to use them for an elegant solution of my problem.
> I can't quite work it out. =A0Any brilliant ideas? =A0 (or other elegant
> solutions to the problem?)

path =3D '/home/gyoung/hacks/pathhack/foo.py'
parts =3D [part for path, part in iter(lambda: os.path.split(path), ('/', '=
'))]
parts.reverse()
print parts

But that's horrendously ugly.  Just write a generator with a while
loop or something.