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Newsgroups: comp.lang.python
Date: Wed, 26 Sep 2012 15:53:40 -0700 (PDT)
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Subject: Re: using "*" to make a list of lists with repeated (and independent) elements
From: 88888 Dihedral <dihedral88888@googlemail.com>
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Xref: csiph.com comp.lang.python:30246

Tim Chase=E6=96=BC 2012=E5=B9=B49=E6=9C=8827=E6=97=A5=E6=98=9F=E6=9C=9F=E5=
=9B=9BUTC+8=E4=B8=8A=E5=8D=886=E6=99=8244=E5=88=8642=E7=A7=92=E5=AF=AB=E9=
=81=93=EF=BC=9A
> On 09/26/12 17:28, 88888 Dihedral wrote:
>=20
> > 88888 Dihedral=E6=96=BC 2012=E5=B9=B49=E6=9C=8827=E6=97=A5=E6=98=9F=E6=
=9C=9F=E5=9B=9BUTC+8=E4=B8=8A=E5=8D=886=E6=99=8207=E5=88=8635=E7=A7=92=E5=
=AF=AB=E9=81=93=EF=BC=9A
>=20
> >>>> In these conditions, how to make this list [[0,0,0],[0,0,0]] with "*=
"=20
>=20
> >>>> without this behavior?
>=20
> >>>     >>> a =3D [[0]*3 for i in xrange(2)]
>=20
> >>>     >>> a[0][0]=3D2
>=20
> >>>     >>> a
>=20
> >>>     [[2, 0, 0], [0, 0, 0]]
>=20
> >=20
>=20
> > def zeros(m,n):
>=20
> > 	a=3D[]
>=20
> > 	for i in xrange(m):
>=20
> > 		a.append([0]*n)
>=20
> > 	return a
>=20
> >=20
>=20
> > If  one wants to tranlate to C, this is the style.
>=20
>=20
>=20
> But this is Python, so why the heck would anybody want to emulate
>=20
> *C* style?  It could also be written in an assembly-language style,
>=20
> COBOL style, or a Fortran style...none of which are particularly
>=20
> valuable.
>=20
>=20
>=20
> Besides, a C-style would allocate a single array of M*N slots and
>=20
> then calculate 2d offsets into that single array. :-P
>=20
>=20
>=20
> -tkc

I don't think a lot programmers can write assembly programs well
for different instruction sets of cpus.

Of course if GCC was not supportd in manny platforms free=20
of charge, then I won't recommend this style of=20
programming in python.