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Xref: csiph.com comp.lang.python:38227

How to reverse the two loops?

On Tuesday, February 5, 2013 2:43:47 PM UTC-5, Dave Angel wrote:
> On 02/05/2013 02:20 PM, maiden129 wrote:
> 
> > On Tuesday, February 5, 2013 1:56:55 PM UTC-5, marduk wrote:
> 
> >> On Tue, Feb 5, 2013, at 01:38 PM, maiden129 wrote:
> 
> >>
> 
> <Snipping double-spaced googlegroups trash>
> 
> >
> 
> > when I removed "s.remove(i), it starts to repeat the number of occurrences too
> 
> >
> 
> > many times like this:
> 
> >
> 
> > 2 occurs 3 times.
> 
> > 2 occurs 3 times.
> 
> > 3 occurs 3 times.
> 
> > 3 occurs 3 times.
> 
> > 2 occurs 3 times.
> 
> > 2 occurs 3 times.
> 
> > 5 occurs 1 time.
> 
> > 3 occurs 3 times.
> 
> > 3 occurs 3 times.
> 
> > 4 occurs 1 time.
> 
> > 3 occurs 3 times.
> 
> > 3 occurs 3 times.
> 
> > 1 occurs 1 time.
> 
> > 2 occurs 3 times.
> 
> > 2 occurs 3 times.
> 
> >
> 
> > How can I stop this?
> 
> >
> 
> 
> 
> As MRAB pointed out, don't delete items from a list you're iterating 
> 
> over.  It can make the iterator go nuts.  He suggests the collections 
> 
> module.
> 
> 
> 
> But if you want to do it by hand, one approach is to reverse the two 
> 
> loops.  Iterate over the characters in CheckS list, examining the entire 
> 
> s list for each one and figuring out how many times the character occurs.
> 
> 
> 
> Another approach is to build a dict, or a defaultdict, to keep counts 
> 
> for each of the characters in CheckS.
> 
> 
> 
> -- 
> 
> DaveA