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Subject: Re: How to turn a string into a list of integers?
From: Kurt Mueller <kurt.alfred.mueller@gmail.com>
In-Reply-To: <CAMw+j7LZu2YWw1UkAYvBnX7LZDJncP5Euh5aYjxYVvWnH=CgwA@mail.gmail.com>
Date: Fri, 5 Sep 2014 21:16:54 +0200
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Xref: csiph.com comp.lang.python:77610


Am 05.09.2014 um 20:25 schrieb Chris =93Kwpolska=94 Warrick =
<kwpolska@gmail.com>:
> On Sep 5, 2014 7:57 PM, "Kurt Mueller" <kurt.alfred.mueller@gmail.com> =
wrote:
> > Could someone please explain the following behavior to me:
> > Python 2.7.7, MacOS 10.9 Mavericks
> >
> > >>> import sys
> > >>> sys.getdefaultencoding()
> > 'ascii'
> > >>> [ord(c) for c in 'A=C4']
> > [65, 195, 132]
> > >>> [ord(c) for c in u'A=C4']
> > [65, 196]
> >
> > My obviously wrong understanding:
> > =82A=C4=91 in =82ascii=91 are two characters
> >      one with ord A=3D65 and
> >      one with ord =C4=3D196 ISO8859-1 <depends on code table>
> >      =97-> why [65, 195, 132]
> > u=92A=C4=92 is an Unicode string
> >      =97-> why [65, 196]
> >
> > It is just the other way round as I would expect.
>=20
> Basically, the first string is just a bunch of bytes, as provided by =
your terminal =97 which sounds like UTF-8 (perfectly logical in 2014).  =
The second one is converted into a real Unicode representation. The =
codepoint for =C4 is U+00C4 (196 decimal). It's just a coincidence that =
it also matches latin1 aka ISO 8859-1 as Unicode starts with all 256 =
latin1 codepoints. Please kindly forget encodings other than UTF-8.

So:
=91A=C4=92 is an UTF-8 string represented by 3 bytes:
A -> 41   -> 65  first byte decimal
=C4 -> c384 -> 195 and 132 second and third byte decimal

u=92A=C4=92 is an Unicode string represented by 2 bytes?:
A -> U+0041 -> 65 first byte decimal, 00 is omitted or not yielded by =
ord()?
=C4 -> U+00C4 -> 196 second byte decimal, 00 is ommited or not yielded =
by ord()?


> BTW: ASCII covers only the first 128 bytes.

ACK
--=20
Kurt Mueller, kurt.alfred.mueller@gmail.com