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Re: How to delete letters automatically with imaplib?

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and how to write the delete command with imaplib?
On 8/6/2014 5:14 PM, Ben Finney wrote:
> elearn <elearn2014@gmail.com> writes:
>
>> status,  data=  con.search(None,  "ALL")
>> print(len(data[0].split()))
>> 48
>> typ,  data=  con.search(None,  'Body',  '"xxx@gmail.com"')
>>>>>   data
>> [b'1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29
>>   32 33 34 35 36 37 44']
>>
>> len(data[0].split())
>> 36
>>
>> How can i delete 48-36=12 letters?
> Set operations are designed for this::
>
>      # Construct a set of all message numbers.
>      status, data = con.search(None, "ALL")
>      ids_of_all_messages = set(data[0].split())
>
>      # Construct a set of messages mentioning the address.
>      status, data = con.search(None, 'Body', '"xxx@gmail.com"')
>      ids_of_messages_containing_address = set(data[0].split())
>
>      # Get the messages to delete.
>      ids_of_messages_to_delete = (
>              ids_of_all_messages - ids_of_messages_containing_address)
>

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Re: How to delete letters automatically with imaplib? elearn <elearn2014@gmail.com> - 2014-08-06 19:19 +0800

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