Path: csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!xlned.com!feeder5.xlned.com!news2.euro.net!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.024 X-Spam-Evidence: '*H*': 0.95; '*S*': 0.00; 'python.': 0.02; 'subject:two': 0.07; 'kumar': 0.09; 'subject:fields': 0.09; 'cc:addr:python-list': 0.11; '203': 0.16; '509': 0.16; 'csv': 0.16; 'finds': 0.16; 'subject:compare': 0.16; 'subject:python': 0.16; 'wrote:': 0.18; 'python?': 0.22; 'cc:addr:python.org': 0.22; 'example.': 0.24; 'question': 0.24; 'cc:2**0': 0.24; 'compare': 0.26; 'header:In-Reply-To:1': 0.27; 'message-id:@mail.gmail.com': 0.30; 'url:mailman': 0.30; 'file': 0.32; 'url:python': 0.33; 'basic': 0.35; 'received:209.85': 0.35; 'received:209.85.220': 0.35; 'received:google.com': 0.35; 'module.': 0.36; 'done': 0.36; 'url:listinfo': 0.36; 'next': 0.36; 'thanks': 0.36; 'url:org': 0.36; 'should': 0.36; 'received:209': 0.37; 'pm,': 0.38; 'url:mail': 0.40; 'how': 0.40; 'numbers': 0.61; 'first': 0.61; 'field': 0.63; 'different': 0.65; '30,': 0.65; 'finally': 0.65; 'here': 0.66; 'study': 0.69; 'joel': 0.91; '2013': 0.98 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:x-received:in-reply-to:references:date:message-id :subject:from:to:cc:content-type; bh=aXCsYXg1D3gDpWtttxy3ZhodzOKCGSHzP1vBOSssVeU=; b=MS7H1hDl/a2EwsEIUHiHrj+XLL2iiZvwwFrflzRFwoNAfKlW1EEwpNnajtriQWVbON +tVe4gTwhuKEqFUXhDXUtX7VEtDLWED4orNgzTPykns0uKrBg8ZqKG7TRJ8lH3GGsLif 3t9fZWCUdR0Poz5hq9NZ05IoKdl8oFHXTxLaKa/cbFgLC0LIIwVKbIVoa8MdOsucEI30 NaqjQmlR2k8xb4sNluMhvTNIR6SP5xCTvipK4yTdMZot3nvh697EopInc5qbCy25sHRL drwAUAhZmKlRY1XqBJ7AHBBOaVMTrtTa0SCTf+5of2rd5AsP4DMhrwZaKF++xhTEPt2c oy9g== MIME-Version: 1.0 X-Received: by 10.220.95.10 with SMTP id b10mr35149164vcn.10.1367344420724; Tue, 30 Apr 2013 10:53:40 -0700 (PDT) In-Reply-To: <59afdc2b-ab76-40b6-8f63-4a562e288029@googlegroups.com> References: <59afdc2b-ab76-40b6-8f63-4a562e288029@googlegroups.com> Date: Tue, 30 Apr 2013 13:53:40 -0400 Subject: Re: how to compare two fields in python From: Joel Goldstick To: upendra kumar Devisetty Content-Type: multipart/alternative; boundary=001a11c1d8787ba6f604db97ae25 Cc: "python-list@python.org" X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 78 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1367344424 news.xs4all.nl 15917 [2001:888:2000:d::a6]:35274 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:44557 --001a11c1d8787ba6f604db97ae25 Content-Type: text/plain; charset=UTF-8 On Tue, Apr 30, 2013 at 1:41 PM, upendra kumar Devisetty < upendrakumar.devisetty@googlemail.com> wrote: > I have a very basic question in python. I want to go through each line of > the a csv file and compare to see if the first field of line 1 is same as > first field of next line and so on. If it finds a match then i would like > to put that field in an object1 else put that field in a different object2. > Finally i would like to count how many of the fields in object1 vs object2. > Can this be done in python? Here is a small example. > > BRM_1 679 1929 > BRM_1 203 567 > BRM_2 367 1308 > BRM_3 435 509 > As you can see field1 of line1 is same as field2 of line2 and so that > field BRM_1 should be place in object1 and BRM_2 and BRM_3 should be placed > in object2. So the final numbers of object1 is 1 and object2 is 2. > > You should study the csv module. > Thanks in advance.. > > Upendra > -- > http://mail.python.org/mailman/listinfo/python-list > -- Joel Goldstick http://joelgoldstick.com --001a11c1d8787ba6f604db97ae25 Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: quoted-printable



On Tue, Apr 30, 2013 at 1:41 PM, upendra kumar Devisetty <upendrakumar.devisetty@googlemail.com> wrote:
I have a very basic question in python. I wa= nt to go through each line of the a csv file and compare to see if the firs= t field of line 1 is same as first field of next line and so on. If it find= s a match then i would like to put that field in an object1 else put that f= ield in a different object2. Finally i would like to count how many of the = fields in object1 vs object2. Can this be done in python? Here is a small e= xample.

BRM_1 =C2=A0 679 1929
BRM_1 =C2=A0 203 567
BRM_2 =C2=A0 367 1308
BRM_3 =C2=A0 435 509
As you can see field1 of line1 is same as field2 of line2 and so that field= BRM_1 should be place in object1 and BRM_2 and BRM_3 should be placed in o= bject2. So the final numbers of object1 is 1 and object2 is 2.


You should study the csv module. =C2= =A0
Thanks in advance..

Upendra
--
http://mail.python.org/mailman/listinfo/python-list



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