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From: Ian Kelly <ian.g.kelly@gmail.com>
Date: Mon, 7 Jul 2014 11:05:44 -0600
Subject: Re: Question about metacharacter '*'
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On Sun, Jul 6, 2014 at 4:49 PM, MRAB <python@mrabarnett.plus.com> wrote:
> \d also matches more than just [0-9] in Unicode.

I think that anything matched by \d will also be accepted by int().

>>> decimals =3D [c for c in (chr(i) for i in range(17 * 2**16)) if unicode=
data.category(c) =3D=3D 'Nd']
>>> len(decimals)
460
>>> re.match(r'\d*', ''.join(decimals)).span()
(0, 460)
>>> int(''.join(decimals))
123456789012345678901234567890123456789012345678901234567890123456789012345=
678901234567890123456789012345678901234567890123456789012345678901234567890=
123456789012345678901234567890123456789012345678901234567890123456789012345=
678901234567890123456789012345678901234567890123456789012345678901234567890=
123456789012345678901234567890123456789012345678901234567890123456789012345=
678901234567890123456789012345678901234567890123456789012345678901234567890=
123456789
>>> nondecimals =3D [c for c in (chr(i) for i in range(17 * 2**16)) if unic=
odedata.category(c) in 'NoNl']
>>> len(nondecimals)
688
>>> re.findall(r'\d', ''.join(nondecimals))
[]