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From: Robin Becker <robin@reportlab.com>
Subject: how to get python socket to use a specific interface
Date: Fri, 23 Oct 2015 10:03:41 +0100
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Xref: csiph.com comp.lang.python:97917

I need to run lynx on a ubuntu headless server with a specific IP address in 
order to try and cancel an email blacklist.

Lynx doesn't provide a way to do that so I thought to use a local proxy. I tried 
pymiproxy and hacked the connection code so it looked like this


proxy.py
........
> from socket import socket, SOL_SOCKET
> .......
> import os
> BIND_ADDRESS = os.environ.get('PYMIPROXY_BIND_ADDRESS',None)
> BIND_DEVICE = os.environ.get('PYMIPROXY_BIND_DEVICE',None)
> .............
>         # Connect to destination
>         sock = self._proxy_sock = socket()
>         sock.settimeout(10)
>         if BIND_ADDRESS:
>             sock.bind((BIND_ADDRESS, 0))
>         if BIND_DEVICE:
>             sock.setsockopt(SOL_SOCKET, 25, BIND_DEVICE)
>         sock.connect((self.hostname, int(self.port)))

25 is derived from /usr/include/asm-generic/socket.h

> #define SO_BINDTODEVICE 25


This works if I export BIND_DEVICE='eth0' and run as root, but my desired 
interface is actually called 'eth0:0' and when I run with that exported I get a 
device error. Does anyone know what I should call the device?
-- 
Robin Becker