Path: csiph.com!fu-berlin.de!uni-berlin.de!not-for-mail From: Newsgroups: comp.lang.python Subject: Re: Nested List question Date: Wed, 24 Feb 2016 17:33:20 -0500 Lines: 74 Message-ID: References: <4AD2810BE3B346399F777EDEAB079BDA@OPTIPLEX990> <56CE2098.2070507@lucidity.plus.com> Mime-Version: 1.0 Content-Type: text/plain; format=flowed; charset="Windows-1252"; reply-type=response Content-Transfer-Encoding: 7bit X-Trace: news.uni-berlin.de Q8qDjo0HRJsxawVkENII+Q9PhDq/W58TbmjoPTCBY27g== Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.061 X-Spam-Evidence: '*H*': 0.88; '*S*': 0.00; 'else:': 0.03; 'wednesday,': 0.07; 'subject:question': 0.08; 'str):': 0.09; 'message-----': 0.15; '2016': 0.16; '24,': 0.16; '303': 0.16; 'erik': 0.16; 'guessing': 0.16; 'mark,': 0.16; 'nest': 0.16; 'received:io': 0.16; 'received:psf.io': 0.16; 'structure.': 0.16; 'wrote:': 0.16; 'nested': 0.18; 'to:2**1': 0.21; 'bit': 0.23; 'tried': 0.24; 'words': 0.24; 'header:In-Reply-To:1': 0.24; 'figure': 0.27; 'question': 0.27; 'that.': 0.30; 'to:name:python- list': 0.30; 'received:10.0.0': 0.32; 'addresses,': 0.33; 'subject:List': 0.33; 'skip:- 10': 0.34; 'correctly': 0.34; 'structure': 0.34; 'received:10.0': 0.34; 'list': 0.34; 'sent:': 0.35; 'could': 0.35; 'park': 0.35; 'something': 0.35; 'subject:': 0.35; 'expected': 0.35; 'but': 0.36; 'list,': 0.36; 'should': 0.36; "wasn't": 0.36; 'to:addr:python-list': 0.36; 'subject:: ': 0.37; 'received:10': 0.37; 'thanks': 0.37; 'list.': 0.37; 'several': 0.38; 'mean': 0.38; 'why': 0.39; 'goes': 0.39; 'data': 0.39; 'from:': 0.39; 'to:addr:python.org': 0.40; 'from:no real name:2**0': 0.60; 'your': 0.60; 'address': 0.61; 'charset:windows-1252': 0.62; 'above,': 0.63; 'more': 0.63; 'you.': 0.64; 'python-list': 0.66; 'apart': 0.70; 'presented': 0.72; 'address,': 0.77; 'received:38': 0.81; 'addresses:': 0.84; 'avenue.': 0.84; 'received:38.111': 0.84; 'surname,': 0.84; 'broadway': 0.91; 'tied': 0.93 X-Scanner-Info: Cloudmark - http://www.cloudmark.com X-CNFS-Analysis: v=2.1 cv=U+Zvdrfu c=1 sm=1 tr=0 a=wmZXJE1MrsZYcnKSeUNejA==:117 a=wmZXJE1MrsZYcnKSeUNejA==:17 a=L9H7d07YOLsA:10 a=9cW_t1CCXrUA:10 a=s5jvgZ67dGcA:10 a=N659UExz7-8A:10 a=43beU8AwAAAA:8 a=v7CqaaOlB21UdseeLJAA:9 a=8ix3We0KtVrtHFCl:21 a=WMAnm43bzIgbgw0i:21 a=pILNOxqGKmIA:10 X-CMAE-Score: 0.00 X-Scanned-by: CMAE X-AUTH-ID: grsmith@atlanticbb.net In-Reply-To: <56CE2098.2070507@lucidity.plus.com> X-Priority: 3 X-MSMail-Priority: Normal Importance: Normal X-Mailer: Microsoft Windows Live Mail 15.4.3555.308 X-MimeOLE: Produced By Microsoft MimeOLE V15.4.3555.308 X-CMAE-Envelope: MS4wfFdp1dR2SFEOMjVNBCTRuYlsQAVBxW0nBjngUpJCTvsnIANor+RrxqSpXk0wLPe6ezHMYo0PB24JTg0FKwyFHs7owYNYKgmy/BV2zUhLpyUhXRXhPbeZyo9tn6dDiqNK8GcGDhfZzprFrhJ5FNInyhzXeUmwx900WBeVgg61CQSBNkmyHYtjIn+Kh/ss0dGeh2W0zZtrL3pK1Jwm/ryoAaE8G7ioNc/wlFzz6MQAP3/XVCInvlXgMp8V3P7C5uFVQA== X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.21rc2 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Xref: csiph.com comp.lang.python:103466 Erik, Works perfectly, thanks much !!! Mark, I am tied to data structure. for address in addresses: if isinstance(address, str): apt = None print(address, apt) else: address, apt = address print(address, apt) 99 First Street None 33 Broadway Avenue Apt 303 1 Park Avenue None -----Original Message----- From: Erik Sent: Wednesday, February 24, 2016 4:28 PM To: grsmith@atlanticbb.net ; python-list Subject: Re: Nested List question On 24/02/16 20:59, grsmith@atlanticbb.net wrote: > Can you have a phython list like: > ['George', > 'Soros', > ['99 First Street', > '33 Broadway Avenue', ['Apt 303'], > '1 Park Avenue'], > 'New York', 'NY'] > > In other words how do you correctly nest the > ['Apt 303'] so it goes with 33 Broadway Avenue. The way to keep those particular items together is to have something like: data = \ ['George', 'Soros', [ '99 First Street', ['33 Broadway Avenue', 'Apt 303'], '1 Park Avenue' ], 'New York', 'NY' ] And then, guessing from the structure of your list, you'd do something like: forename, surname, addresses, city, state = data And then, something like: for address in addresses: if type(address) == StringType: apt = None else: address, apt = address That should work to pick apart with what you have presented above, but I think you'd be better off presenting the data with a bit more structure in the first place. > Also, I tried several ways and could not figure out > how to get the ['Apt 303'] out of the list. How can > you do that. It would be much easier to work out what you mean by this if you'd have actually said what you'd tried and what you had expected to happen and why what did happen wasn't right for you. E.