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Date: Thu, 25 Apr 2013 23:37:53 +0100
Subject: Re: baffled classes within a function namespace. Evaluation order.
From: Alastair Thompson <hexforge@gmail.com>
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Thats a good pointer to what is going on. Thank you Bas.

I am familiar with error such as

x=1
def foo():
    x = 2
    def erm():
        print(x)
        x=3
    erm()
foo()
UnboundLocalError: local variable 'x' referenced before assignment.

It seems a bit different for classes (below), as it jumps out to get the
value from the global name space, where it didn't for functions (above).

x=1
def foo():
    x = 2
    class erm():
        print(x)
        x = 3
foo()      # This evaluates == 1

But you certainly have explained why  "NameError: name 'third' is not
defined" occurs.

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<div dir=3D"ltr"><div><div><div>Thats a good pointer to what is going on. T=
hank you Bas.<br><br></div>I am familiar with error such as<br><br>x=3D1<br=
>def foo():<br>=A0 =A0 x =3D 2<br>=A0 =A0 def erm():<br>=A0 =A0 =A0 =A0 pri=
nt(x)<br>=A0 =A0 =A0 =A0 x=3D3<br>

=A0 =A0 erm()<br>foo()=A0 <br>UnboundLocalError: local variable &#39;x&#39;=
 referenced before assignment.<br><br></div>It
 seems a bit different for classes (below), as it jumps out to get the=20
value from the global name space, where it didn&#39;t for functions (above)=
.<br>
<br>x=3D1<br>def foo():<br>=A0 =A0 x =3D 2<br>=A0 =A0 class erm():<br>=A0 =
=A0 =A0 =A0 print(x)<br></div><div>=A0=A0=A0=A0=A0=A0=A0 x =3D 3<br></div><=
div>foo() =A0 =A0=A0 # This evaluates =3D=3D 1=A0 <br><br></div>But you cer=
tainly have explained why=A0 &quot;NameError: name &#39;third&#39; is not d=
efined&quot; occurs.</div>

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