Path: csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!eu.feeder.erje.net!news.stack.nl!newsfeed.xs4all.nl!newsfeed1.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.002 X-Spam-Evidence: '*H*': 1.00; '*S*': 0.00; 'else:': 0.03; 'preferable': 0.09; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'try:': 0.09; 'collections': 0.16; 'received:80.91.229.3': 0.16; 'received:plane.gmane.org': 0.16; 'import': 0.22; 'header:User- Agent:1': 0.23; 'header:X-Complaints-To:1': 0.27; 'header:In- Reply-To:1': 0.27; 'chris': 0.29; 'keyerror:': 0.31; 'except': 0.35; 'but': 0.35; '8bit%:86': 0.38; 'to:addr:python-list': 0.38; 'to:addr:python.org': 0.39; 'received:org': 0.40; 'course': 0.61 X-Injected-Via-Gmane: http://gmane.org/ To: python-list@python.org From: Serhiy Storchaka Subject: Re: Pythonic way to count sequences Date: Thu, 25 Apr 2013 15:36:47 +0300 References: Mime-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit X-Gmane-NNTP-Posting-Host: 95.111.210.101 User-Agent: Mozilla/5.0 (X11; Linux i686; rv:17.0) Gecko/20130329 Thunderbird/17.0.5 In-Reply-To: X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.15 Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Newsgroups: comp.lang.python Message-ID: Lines: 31 NNTP-Posting-Host: 2001:888:2000:d::a6 X-Trace: 1366893429 news.xs4all.nl 15959 [2001:888:2000:d::a6]:51306 X-Complaints-To: abuse@xs4all.nl Xref: csiph.com comp.lang.python:44334 25.04.13 08:26, Chris Angelico написав(ла): > So you can count them up directly with a dictionary: > > count = {} > for sequence_tuple in list_of_tuples: > count[sequence_tuple] = count.get(sequence_tuple,0) + 1 Or alternatives: count = {} for sequence_tuple in list_of_tuples: if sequence_tuple] in count: count[sequence_tuple] += 1 else: count[sequence_tuple] = 1 count = {} for sequence_tuple in list_of_tuples: try: count[sequence_tuple] += 1 except KeyError: count[sequence_tuple] = 1 import collections count = collections.defaultdict(int) for sequence_tuple in list_of_tuples: count[sequence_tuple] += 1 But of course collections.Counter is a preferable way now.