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Xref: csiph.com comp.lang.python:37674

On Friday, January 25, 2013 9:04:31 PM UTC+8, Dave Angel wrote:
> On 01/25/2013 07:06 AM, moonhkt wrote:
> 
> > Hi All
> 
> >
> 
> > Python 2.6.x on AIX
> 
> >
> 
> > Data file
> 
> >
> 
> > PrinterA
> 
> >        print Production batch1
> 
> >               xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> 
> >        print Production batch2
> 
> >               xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> 
> >        print Production batch3
> 
> >             xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> 
> >
> 
> > PrinterB
> 
> >       print Production batch4
> 
> >             xxxxxxxxxxxxxxxxxxxxxxxxxxx
> 
> >        print Production batch5
> 
> >            xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> 
> >
> 
> >
> 
> > What to using python create object base on date file ? I know how to
> 
> > read text file.
> 
> >
> 
> > object["PrinterA"] have  batch1,  batch2,  batch3
> 
> >
> 
> > object["PrinterB"] have  batch4, batch5
> 
> >
> 
> > moonhkt
> 
> >
> 
> 
> 
> What Python version are you targeting?
> 
> 
> 
> It would save everyone a lot of time if you quoted the homework 
> 
> assignment directly.  Also, be more careful about typos.  Is it a date 
> 
> file, or a data file?
> 
> 
> 
> You can create an object very easily.  a = object().  You can add 
> 
> attributes to many objects by simply saying
> 
>      a.attrib = 42
> 
> 
> 
> Unfortunately you can't do that to an "object" class instance.  So you 
> 
> need to clarify.
> 
> 
> 
> Now, you used dictionary syntax, so perhaps you didn't mean create an 
> 
> object, but create a dict.
> 
> 
> 
> a = dict()
> 
> a["PrinterA"] = "batch1", "batch2", "batch3"
> 
> print a
> 
> 
> 
> produces
> 
> {'PrinterA': ('batch1', 'batch2', 'batch3')}
> 
> 
> 
> 
> 
> What part of the assignment is giving you trouble?  What have you 
> 
> written so far?
> 
> 
> 
> 
> 
> -- 
> 
> DaveA

Thank I get the methods. 
Python 2.6.2

I just leaning python , before using gawk/ksh.

#!/usr/bin/env python

a= dict()
a["PrintA"]= ["batch1","batch2","batch3"]
a["PrintB"] = ["batch4","batch5"]

a["PrintA"].append("batch6")

print a
for k in sorted(a.keys()):
    for j in sorted(a[k]):
     print k , j

Output 
{'PrintA': ['batch1', 'batch2', 'batch3', 'batch6'], 'PrintB': ['batch4', 'batch5']}
PrintA batch1
PrintA batch2
PrintA batch3
PrintA batch6
PrintB batch4
PrintB batch5