Received: by 10.224.223.77 with SMTP id ij13mr833175qab.1.1346235746192; Wed, 29 Aug 2012 03:22:26 -0700 (PDT)
Received: by 10.52.180.202 with SMTP id dq10mr64631vdc.17.1346235746165; Wed, 29 Aug 2012 03:22:26 -0700 (PDT)
Path: csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!news.glorb.com!r1no2729879qas.0!news-out.google.com!da15ni48885608qab.0!nntp.google.com!r1no2729877qas.0!postnews.google.com!glegroupsg2000goo.googlegroups.com!not-for-mail
Newsgroups: comp.lang.python
Date: Wed, 29 Aug 2012 03:22:26 -0700 (PDT)
In-Reply-To: <1c7cd833-b6ad-4a17-8ffe-a0ce20c8f400@googlegroups.com>
Complaints-To: groups-abuse@google.com
Injection-Info: glegroupsg2000goo.googlegroups.com; posting-host=2.229.102.162; posting-account=5n9o1QoAAAClfHc4fQdLBCN15pyoz8MM
NNTP-Posting-Host: 2.229.102.162
References: <1c7cd833-b6ad-4a17-8ffe-a0ce20c8f400@googlegroups.com>
User-Agent: G2/1.0
MIME-Version: 1.0
Message-ID: <c92e1fdc-ff14-4484-9e03-e322de9ba82b@googlegroups.com>
Subject: Re: What do I do to read html files on my pc?
From: mikcec82 <michele.cecere@gmail.com>
Injection-Date: Wed, 29 Aug 2012 10:22:26 +0000
Content-Type: text/plain; charset=ISO-8859-1
Content-Transfer-Encoding: quoted-printable
Xref: csiph.com comp.lang.python:28052

Il giorno luned=EC 27 agosto 2012 12:59:02 UTC+2, mikcec82 ha scritto:
> Hallo,
>=20
>=20
>=20
> I have an html file on my pc and I want to read it to extract some text.
>=20
> Can you help on which libs I have to use and how can I do it?
>=20
>=20
>=20
> thank you so much.
>=20
>=20
>=20
> Michele

Hi Peter and thanks for your precious help.
Fortunately, there aren't runs of "X" with repeats other than 2 or 4.
Starting from your code, I wrote this code (I post it, so it could be helpf=
ul for other people):
f =3D open(fileorig, 'r')=20
nomefile =3D f.read()

start =3D nomefile.find("XX")
start2 =3D nomefile.find("NOT PASSED")
c0 =3D 0
c1 =3D 0
c2 =3D 0

while (start !=3D -1) | (start2 !=3D -1):
   =20
    if nomefile[start:start+4] =3D=3D "XXXX":=20
        print "XXXX       found at location", start
        start +=3D 4
        c0 +=3D1
    elif nomefile[start:start+2] =3D=3D "XX":
        print "XX         found at location", start
        start +=3D 2
        c1 +=3D1
       =20
    if nomefile[start2:start2+10] =3D=3D "NOT PASSED":=20
        print "NOT PASSED found at location", start2
        start2 +=3D 10
        c2 +=3D1

    start =3D nomefile.find("XX", start)
    start2 =3D nomefile.find("NOT PASSED", start2)

print "XXXX       %s founded" % c0, "\nXX         %s founded" % c1, "\nNOT =
PASSED %s founded" % c2

Now, I'm able to find all occurences of strings: "XXXX", "XX" and "NOT PASS=
ED"=20


Thank you so much.