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From: Helmut Jarausch <jarausch@igpm.rwth-aachen.de>
Newsgroups: comp.lang.python
Subject: Re: extracting a heapq in a for loop - there must be  more elegant solution
Date: 4 Dec 2013 09:37:08 GMT
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On Tue, 03 Dec 2013 04:40:26 -0800, rusi wrote:

> On Tuesday, December 3, 2013 5:48:59 PM UTC+5:30, Helmut Jarausch wrote:
>> Hi,
>>
>> I'd like to extracted elements from a heapq in a for loop.
>> I feel my solution below is much too complicated.
>> How to do it more elegantly? 
>> I know I could use a while loop but I don't like it.
> 
> How about
> 
> def in_sequence(h):
>   for i in range(len(h)):
>     yield heapq.heappop(h)
> 
> Yeah its a bit fiddly:
> 1. i needed for for but not used
> 2. The range in the for loop -- normally a python 'smell'
> 
> If python3
> 
> def ins3(h):
>    yield from (heapq.heappop(h) for i in range(len(h)))

Many thanks, I'm using Python3 anyway!
Helmut