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From: Neil Cerutti <neilc@norwich.edu>
Newsgroups: comp.lang.python
Subject: Re: First day beginner to python, add to counter after nested loop
Date: 29 Oct 2013 20:32:50 GMT
Organization: Norwich University
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On 2013-10-29, jonas.thornvall@gmail.com
<jonas.thornvall@gmail.com> wrote:
> Got the script working though :D, good start. It seem though
> that Python automaticly add linebreaks after printout. Is there
> a way to not have print command change line? Or must i build up
> a string/strings for later printout?

print takes an keyword argument, called end, that defaults to
"\n". You can provide something else:

print("xzzz", end="")

> #!/usr/bin/python
> import math
> # Function definition is here
> def sq(number):
>       square=1;

Get in the habit of not using the semicolon to end lines. Python
doesn't need them, except when two statements appear without a
newline between them.

>       factor=2;
>       exponent=2;
>       print(x,"= ");

That ought to be

        print(number, "= ", end="")

There's no need to refer to global x when you've passed it in as
number.

>       while (number>3):
>          while (square<=number):
>             factor+=1;
>             square=math.pow(factor,exponent);

You don't want to use math.pow. Just use pow or the ** operator.

         square = factor**exponent

>          factor-=1;	
>          print(factor,"^2");
>          square=math.pow(factor,exponent);
>          number=number-(factor*factor);

Analogous with factor += 1, you can do

          number -= factor * factor

Note the usual spacing of python operators and identifiers.

>          square=1; 
>          factor=1;
>       print("+",number);
>       return

A bare return at the end of a Python function is not needed. All
functions return None if they fall off the end.

-- 
Neil Cerutti