Path: csiph.com!usenet.pasdenom.info!news.albasani.net!fu-berlin.de!uni-berlin.de!individual.net!not-for-mail From: Neil Cerutti Newsgroups: comp.lang.python Subject: Re: howto handle nested for Date: 28 Sep 2012 20:38:56 GMT Organization: Norwich University Lines: 63 Message-ID: References: Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit X-Trace: individual.net qzgNrD3eZz1wWFfhvJbm+wArd0btlH1kzE1kpKoyO5nMPkyg3H7UcOCiLZO8VoBF7O Cancel-Lock: sha1:LskeCUf5aHQJwvuBKYC+b60sPp4= User-Agent: slrn/0.9.9p1/mm/ao (Win32) Xref: csiph.com comp.lang.python:30428 On 2012-09-28, Laszlo Nagy wrote: > In your example, it seem that the iterable of the for loop is > always the same: range(n_sysms). It seems to be a number. Is > that true? If that is so, then here is something useful: > > import copy > > class MultiLevelIterator(object): > def __init__(self,levels,n): > assert(levels>0) > assert(n>0) > self.levels = levels > self.values = [0]*levels > self.n = n > > def __iter__(self): > return self > > def next(self): > res = copy.copy(self.values) > idx = self.levels-1 > while idx>=0: > self.values[idx]+=1 > if self.values[idx]>=self.n: > self.values[idx] = 0 > idx-=1 > else: > return res > raise StopIteration > > i = MultiLevelIterator(2,3) > for values in i: > print values > > This will print: > > [0, 0] > [0, 1] > [0, 2] > [1, 0] > [1, 1] > [1, 2] > [2, 0] > [2, 1] It looks like you might have missed the last one. Also, be sure to check itertools for occasionally for cool stuff like this. >>> for values in itertools.product(range(3), repeat=2): ... print(values) ... (0, 0) (0, 1) (0, 2) (1, 0) (1, 1) (1, 2) (2, 0) (2, 1) (2, 2) -- Neil Cerutti