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From: Tom P <werotizy@freent.dd>
Newsgroups: comp.lang.python
Subject: Re: looking for a neat solution to a nested loop problem
Date: Mon, 06 Aug 2012 21:03:30 +0200
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Xref: csiph.com comp.lang.python:26647

On 08/06/2012 08:29 PM, Grant Edwards wrote:
> On 2012-08-06, Grant Edwards <invalid@invalid.invalid> wrote:
>> On 2012-08-06, Tom P <werotizy@freent.dd> wrote:
>>> On 08/06/2012 06:18 PM, Nobody wrote:
>>>> On Mon, 06 Aug 2012 17:52:31 +0200, Tom P wrote:
>>>>
>>>>> consider a nested loop algorithm -
>>>>>
>>>>> for i in range(100):
>>>>>        for j in range(100):
>>>>>            do_something(i,j)
>>>>>
>>>>> Now, suppose I don't want to use i = 0 and j = 0 as initial values, but
>>>>> some other values i = N and j = M, and I want to iterate through all
>>>>> 10,000 values in sequence - is there a neat python-like way to this?
>>>>
>>>> 	for i in range(N,N+100):
>>>> 	    for j in range(M,M+100):
>>>> 	        do_something(i,j)
>>>>
>>>> Or did you mean something else?
>>>
>>> no, I meant something else ..
>>>
>>>     j runs through range(M, 100) and then range(0,M), and i runs through
>>> range(N,100) and then range(0,N)
>>
>> In 2.x:
>>
>>      for i in range(M,100)+range(0,M):
>>          for j in range(N,100)+range(0,N):
>>              do_something(i,j)
>>
>> Dunno if that still works in 3.x.  I doubt it, since I think in 3.x
>> range returns an iterator, not?
>
> Indeed it doesn't work in 3.x, but this does:
>
>      from itertools import chain
>
>      for i in chain(range(M,100),range(0,M)):
>          for j in chain(range(N,100),range(0,N)):
>              do_something(i,j)
>
>
  ah, that looks good - I guess it works in 2.x as well?