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Newsgroups: comp.lang.python
Date: Wed, 18 Jun 2014 23:48:00 -0700 (PDT)
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Subject: Re: how to check if a value is a floating point or not
From: Nicholas Cannon <nicholascannon1@gmail.com>
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Xref: csiph.com comp.lang.python:73394

On Thursday, June 19, 2014 1:53:31 PM UTC+8, Nicholas Cannon wrote:
> I am making a calculator and i need it to support floating point values b=
ut i am using the function isnumeric to check if the user has entered an in=
t value. I need the same for floating point types so i could implement an o=
r in the if statement that checks the values the user has entered and allow=
 it to check and use floating points. If you need the source code i am happ=
y to give it to you. Thank you for your help

I am using python 2.7.7 and i have come up with away but there is still pos=
sible errors for this. What i did was i this

#checks if the user input is an integer value
def checkint(a):
	if a.isnumeric():
		return True
	else:
		if a.isalpha():
			return False
		else:
			return True

The parameter a is the users input by the raw_input function. I first test =
if it is normal int with the isnumeric function. Unfortunately this functio=
n picks up the decimal as false. This means if the user inputs a float it h=
as to be false. I then test if this input has any alphabetical characters i=
f it does not the user could have only entered  something like 12.5 oppose =
to abc.d. This method works fine and it i have  tested it and it works fine=
. if incase this input did have a letter it would be picked up by the isalp=
ha function. There is one annoying error doing it this way and that is if y=
ou enter 12.ab or ab.12 it will say that it is okay. Still working on this =
so this should get sorted out soon.