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Message-ID: <1905065.XAFRqVoOGU@PointedEars.de>
From: Thomas 'PointedEars' Lahn <PointedEars@web.de>
Reply-To: Thomas 'PointedEars' Lahn <usenet@PointedEars.de>
Organization: PointedEars Software (PES)
Date: Fri, 20 May 2011 09:38:48 +0200
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Subject: Re: connect SIGINT to custom interrupt handler
Newsgroups: comp.lang.python
References: <slrnisv835.b74.chris@scheingraber.no-ip.org> <pan.2011.05.15.13.08.22.15000@nowhere.com> <slrnisvove.dj0.chris@scheingraber.no-ip.org> <1691845.hkbZ0PkbqX@PointedEars.de> <slrnit01vm.hf2.spam@scheingraber.no-ip.org>
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Christoph Scheingraber wrote:

> On 2011-05-15, Thomas 'PointedEars' Lahn <PointedEars@web.de> wrote:
>> Obviously.  `signal' refers to an `int' object, probably by something
>> like
>>
>>   signal = 42
>>
>> before.  E.g. `print' or a debugger will tell you, as you have not showed
>> the relevant parts of the code.
> 
> The problem is that I am running someone else's module which seems to
> use signal, I guess that means I have to create a child method?
> Is it correct anyway to have
> 
> signal.siginterrupt(signal.SIGINT, False)
> 
> in my custom interrupt_handler function

Only if `signal' is not the name of an int argument.

> or should it be outside but
> after signal.signal(signal.SIGINT, interrupt_handler)?

In the meantime, Chris Angelico has pointed out the cause of the problem.  
Please follow his advice, i.e. rename your argument.

-- 
PointedEars

Bitte keine Kopien per E-Mail. / Please do not Cc: me.