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Message-ID: <6874852.M4kG57y0yY@PointedEars.de>
From: Thomas 'PointedEars' Lahn <PointedEars@web.de>
Reply-To: Thomas 'PointedEars' Lahn <cljs@PointedEars.de>
Organization: PointedEars Software (PES)
Date: Tue, 18 Oct 2011 19:48:36 +0200
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Subject: Re: Objects comparaison ?
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John G Harris wrote:

> Thomas 'PointedEars' Lahn wrote:
>> Andreas Bergmaier wrote:
>>> And what do you mean with "it has parameters"? Attaching a function
>>> without parameters, or attaching a non-function property would be OK?
>> He is confusing this with Object.prototype.equals(obj1, obj2),
> 
> It's not me that's confused. You attached the function to Object, a
> constructor. That is what I was commenting on.

In order to save yourself from further embarassment, you really want to have 
at least a look at the ECMAScript Language Specification, Edition 5 Final, 
before further commenting on the programming that is on-topic here.

>> which would be a rather bad idea indeed, for two reasons:
>>
>> First, it would show up in for-in iteration as it would be enumerable
>> (and it remains to be seen how widely Object.defineProperty() is
>> implemented, so that this can be prevented).
>>
>> Second, the conflict between the `this' value and one of the arguments
>> needs to be resolved: Which value refers to the object being compared
>> against?
>   <snip>
> 
> There is no conflict. Which values are to be compared is resolved by the
> function's specification. You do have one, don't you? From the displayed
> code it appears to be obj1 and obj2; the this value is not used.

I was talking about the other way to implement this, 
Object.prototype.equals(), in that paragraph, as can be seen further above.  
Assuming it would be implemented that way,

  Object.prototype.equals = function(obj1, obj2) {
    …
  };

then Object instances (and all objects that inherit from [the object 
referred to by] Object.prototype through their prototype chain) would 
inherit that method (which is part of why that is not a good idea at the 
moment).  Then it would be possible to call

  ({}).equals(foo, bar);

and one would need to decide in one's implementation what value acts as the 
`this' value in the equals() code, if any: either that of `foo', or that of 
`bar'.  (My recommendation stands that it should be that of `bar'.)

Such considerations do not have to be made if you have a "static" method 
that is not inherited by other objects implicitly, as in the first approach.  
Those methods are not supposed to be transferred to other objects.


PointedEars
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