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From: Travers Naran <tnaran@gmail.com>
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Subject: Re: A freshman's question
Date: Thu, 20 Oct 2011 07:30:31 -0700
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On 18/10/2011 8:48 PM, Patricia Shanahan wrote:
>
> The i=i++ operation sequence is:
>
> 1. Evaluate i++. It has the side effect of incrementing i to 1, but has
> as result the old value of i, 0.
>
> 2. Do the assignment. This sets the left hand side, i, equal to the
> result of the right hand side, 0.
>
> In theory, i does change to 1, but immediately changes back to 0. In
> practice, the change in i's value might get optimized out. The effect of
> i=i++ is to leave i unchanged.

This is off topic, but I just recently learned that in C++, the result 
of i=i++ is officially undefined.  It's interesting a question related 
to what I learned comes up again in a completely different forum.