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From: Robert Klemme <shortcutter@googlemail.com>
Newsgroups: comp.lang.java.programmer
Subject: Re: It doesn't like 'super' where ever I put it.
Date: Tue, 12 Jun 2012 18:21:52 +0200
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On 12.06.2012 02:38, Lew wrote:
> Stefan Ram wrote:
>> Eric Sosman writes:
>>> Constructor must call super() or this() before return in
>>> method CalcFrame1.<init>()V [...] (...)
>>> at hand, and the compiler has no way to know which was intended.
>>
>>    But the above is not a compiler message, but a run-time message.
>
> Perhaps there was a transcription error in the OP's message when they p=
ut
> together their otherwise quite serviceable SSCCE.

I rather think the confusion now reached a degree where people loose=20
sight of compile time and runtime. :-)

>>    For a similar situation, I get a compiler message:
>>
>> |Main.java:31: error: call to super must be first statement in constru=
ctor
>> |public void test(){ super(); }
>>
>>    . (This message does not actually claim that =BBtest=AB was a
>>    constructor, although one might read it this way.)
>
> Has anyone tried compiling the OP's first example? (I haven't, and won'=
t.)
> Perhaps there's a further anomaly in there.

Yes, with Eclipse.  See my posting from yesterday for Eclipse _compiler_ =

(and not runtime!) error message.  Repeated for convenience:

> Granted, the error message is probably not the most telling.  Eclipse s=
ays
> Constructor call must be the first statement in a constructor CalcFrame=
1.java    /c.l.j.p/src    line 8    Java Problem
>
> Which is certainly clearer.

Kind regards

	robert

--=20
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/