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From: Lew <lewbloch@gmail.com>
Newsgroups: comp.lang.java.programmer
Subject: Re: It doesn't like 'super' where ever I put it.
Date: Mon, 11 Jun 2012 16:42:55 -0700 (PDT)
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Martin Gregorie wrote:
> Gavino wrote:
>> Robert Klemme wrote ...
>> Gavino wrote:
>>>> It can't because the superclass (JFrame) does not have a constructor
>>>> without arguments.
>> 
>>> Also wrong.
>> 
>>> <http://docs.oracle.com/javase/6/docs/api/javax/swing/JFrame.html#JFrame()>
>> 
>> My apologies.
>> I don't know where I got that erroneous idea from, but somehow I've been
>> carrying it around in my head for the last 12 years.
>> I should have checked the JavaDocs instead of relying on badly
>> remembered information.
>> 
>> Now I'm equally confused about the wording of the error message.
> 
> As Stefan said, I believe its objecting to the call to 
> super("CalcFrame1") in the class erroneously declared as 
> "public void CalcFrame1()".

Here's the chain: 

The rule for 'super()' constructor calls is that they must appear only as the first line in a constructor. The OP put it in a different place, inside a method, violating the rule stated in the error message: 
"Constructor must call super() or this() before return in method CalcFrame1.<init>()V at offset 0"

That's not where the OP's code called 'super()'. Ergo, it violated that rule.

-- 
Lew