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From: Keith Thompson <Keith.S.Thompson+u@gmail.com>
Newsgroups: comp.lang.c
Subject: Re: _BitInt(N)
Date: Sun, 30 Nov 2025 17:32:31 -0800
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Michael S <already5chosen@yahoo.com> writes:
[...]
> Now, if you ask me, I don't understand why Waldek Hebisch considers
> difference between 8-bit and [byte-addressable] 16-bit targets
> important. As far as size of relevant C types goes, they look the same: 
> char - 8 bits
> int - 16 bit
> long - 32 bits
> There is possibly difference in the size of 'short', but I don't
> understand why it matters.

Given 16-bit int, short is almost certain to be 16 bits as well.

char is requires to be at least 8 bits, short and int at least 16, and
long at least 32 (and long long at least 64).

Or is 8-bit short used in some non-conforming mode?

-- 
Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.com
void Void(void) { Void(); } /* The recursive call of the void */