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Re: Lamda as Operator Overload

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On Wednesday, 27 April 2016 13:50:10 UTC+2, Adi Shavit  wrote:
> Is it possible to create a lambda that behaves like an operator
> overload? 
> That is, instead of calling it with the operator() syntax, it will be
> called by some other, e.g. binary, infix operator.
> 
> Is it possible to generically simulate this somehow just like lambdas
> can as structs overloading the () operator. The problem is just how to
> get the compiler/ADL to call the correct function based on the operator.

I don't see how.  The point about a lambda is that it creates a thing
without a name (that you can then store in a named variable, but the thing
itself is nameless), whereas operator overloading works precisely on the
basis of the name of the (member)function.


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Lamda as Operator Overload Adi Shavit <adishavit@googlemail.com> - 2016-04-27 06:46 -0600
  Re: Lamda as Operator Overload Öö Tiib <ootiib@hot.ee> - 2016-04-27 08:44 -0600
    Re: Lamda as Operator Overload Kalle Olavi Niemitalo <kon@iki.fi> - 2016-04-27 15:21 -0600
      Re: Lamda as Operator Overload Adi Shavit <adishavit@googlemail.com> - 2016-04-27 17:13 -0600
        Re: Lamda as Operator Overload Öö Tiib <ootiib@hot.ee> - 2016-04-28 06:30 -0600
  Re: Lamda as Operator Overload Martin Bonner <martinfrompi@yahoo.co.uk> - 2016-04-27 08:44 -0600
    Re: Lamda as Operator Overload Adi Shavit <adishavit@googlemail.com> - 2016-04-27 15:14 -0600

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