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From: valerasimonov@gmail.com
Newsgroups: comp.graphics.apps.gnuplot
Subject: Re: How to print floats with leading blanks instead of leading zeros using sprintf?
Date: Mon, 28 May 2012 20:19:58 -0700 (PDT)
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On Monday, May 28, 2012 2:16:26 PM UTC-4, sfeam wrote:
> =D0=92=D0=B0=D0=BB=D0=B5=D1=80=D0=B8=D0=B9 =D0=A1=D0=B8=D0=BC=D0=BE=D0=BD=
=D0=BE=D0=B2 wrote:
>=20
> > Hi everyone,
> >=20
> > I want to specify labels for the plots using sprintf.
> > According to
> > http://www.cplusplus.com/reference/clibrary/cstdio/sprintf/ sprintf('
> > %3.0f',1) should print "001"
> > sprintf(' %3.0d',1) should print "  1".
> > However gnuplot outputs:
> > sprintf(' %3.0f',1)  "001"
> > sprintf(' %3.0d',1) "1" (without leading blanks).
> >=20
> > Does anyone know how to fix this issue?
>=20
> I cannot reproduce either of those results here.
> The first one in particular makes no sense.
> Could it be that you are not really using the format you show us?
>=20
>  gnuplot> print sprintf("|%3.0d|",1)
>  |  1|
>  gnuplot>
>=20
>=20
> >=20
> > Thanks in advance!
> >=20
> > Regards,
> > Valera

sfeam, thank you for your reply.

I will provide some more details.

I want to plot the file:
"sprintf.txt"
0.2	1.5970E-01	1.1262E-01
0.4	5.7188E-01	2.2227E-01
0.6	2.2019E-01	4.3648E-01

executing the following script: ./plot_sprintf 20 1
#!/bin/sh
gnuplot << EOF
set terminal postscript eps enhanced
set output 'plot_sprintf.eps'
plot "sprintf.txt" using (\$1):(\$2) w l ls 1 t sprintf('T > %03.0f  abc',$=
1),\
     "sprintf.txt" using (\$1):(\$3) w l ls 2 t sprintf('T > %3d  abc',$2)
unset table
EOF

After the script execution I get an eps file with the following strings tha=
t "don't align properly": they look approximately like this
T > 020 abc
 T >  1 abc
instead of looking like this (the way I want):
T > 020 abc
T >   1 abc.

As Hans-Bernhard mentioned I used %d specifier for printing a float, which =
is of course wrong. Actually all the "floats" I provide for sprintf can be =
converted into integers (so these floats are 20.0 and 1.0 in the above exam=
ple). I used %d because I started trial and error method just to get what I=
 want.=20

P.S.
In the reference it was written:
"Minimum number of characters to be printed. If the value to be printed is =
shorter than this number, the result is padded with blank spaces. The value=
 is not truncated even if the result is larger."
So specifying sprintf('T > %3.0f  abc', 1) I expected to see desired blanks=
, but I didn't. Than I started applying "everything you can try" method.
By the way sprintf('T > %3.0f  abc', 1) did the same job as  sprintf('T > %=
3d  abc', 1). However  sprintf('T > %5d  abc', 1) had the desired output fo=
rm
T > 020 abc
T >   1 abc
but only for 1 digit numbers.

Sorry, I did a pretty bad job writing my first post.