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Groups > comp.arch.arithmetic > #61
| From | Quadibloc <jsavard@ecn.ab.ca> |
|---|---|
| Newsgroups | comp.arch, comp.arch.arithmetic |
| Subject | Re: IEEE-754-2008 standard questions |
| Date | 2012-02-05 14:05 -0800 |
| Organization | http://groups.google.com |
| Message-ID | <8bd564cc-a056-492b-94c0-e198af32ee97@x6g2000pbk.googlegroups.com> (permalink) |
| References | <53380dad-61fc-492e-ba4b-336bd70e5b09@vh10g2000pbc.googlegroups.com> |
Cross-posted to 2 groups.
On Feb 4, 9:18 pm, Daku <dakup...@gmail.com> wrote: > So, given all of this, how would one convert > a number from the IEEE-754-2008 format > to the standard human understandable form. I'm not understanding your question. The fact that there is a "hidden bit" doesn't make it that much more difficult to convert such a number to a human-readable value. All that's needed is to read the standard carefully enough to know exactly where to place the binary point - exactly what offset is to be applied to the exponent. Everything else is just about the same as converting any other floating-point format. John Savard
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IEEE-754-2008 standard questions Daku <dakupoto@gmail.com> - 2012-02-04 20:18 -0800 Re: IEEE-754-2008 standard questions Quadibloc <jsavard@ecn.ab.ca> - 2012-02-05 14:05 -0800 Re: IEEE-754-2008 standard questions Brian Drummond <brian@shapes.demon.co.uk> - 2012-02-07 09:43 +0000
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